From: Tobias Grosser <grosser@fim.uni-passau.de>
To: Richard Guenther <richard.guenther@gmail.com>
Cc: gcc@gcc.gnu.org, Sebastian Pop <sebpop@gmail.com>,
Li Feng <nemokingdom@gmail.com>,
gcc-graphite <gcc-graphite@googlegroups.com>
Subject: Re: How could I get alias set information from data_reference_p
Date: Wed, 15 Jul 2009 23:16:00 -0000 [thread overview]
Message-ID: <1247699704.87884.423.camel@localhost> (raw)
In-Reply-To: <15137_1247690941_4A5E40BC_15137_586_1_84fc9c000907151348s41395cc5u6cfacb60cde78bfa@mail.gmail.com>
On Wed, 2009-07-15 at 22:48 +0200, Richard Guenther wrote:
> On Wed, Jul 15, 2009 at 10:46 PM, Richard
> Guenther<richard.guenther@gmail.com> wrote:
> > On Wed, Jul 15, 2009 at 9:15 PM, Tobias
> > Grosser<grosser@fim.uni-passau.de> wrote:
> >>> A note on Lis final graph algorithm. I don't understand why you want
> >>> to allow data-references to be part of multiple alias-sets? (Of course
> >>> I don't know how you are going to use the alias-sets ...)
> >>
> >> Just to pass more information to Graphite. The easiest example might be
> >> something like
> >>
> >> A -- B -- C
> >>
> >> if we have
> >>
> >> AS1 = {A,B}
> >> AS2 = {B,C}
> >>
> >> we know that A and C do not alias and therefore do not have any
> >
> > No, from the above you _don't_ know that. How would you arrive
> > at that conclusion?
>
> What I want to say is that, if A -- B -- C is supposed to be the alias graph
> resulting from querying the alias oracle for the pairs (A, B), (A, C), (B, C)
> then this is a result that will never occur. Because if (A, B) is true
> and (B, C) is true then (A, C) will be true as well.
What for example for this case:
void foo (*b) {
int *a
int *c
if (bar())
a = b;
else
c = b;
}
I thought this may give us the example above, but it seems I am wrong.
If the alias oracle is transitive that would simplify the algorithm a
lot. Can we rely on the transitivity?
Tobi
next prev parent reply other threads:[~2009-07-15 23:16 UTC|newest]
Thread overview: 22+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-07-14 6:01 Li Feng
2009-07-14 8:54 ` Richard Guenther
2009-07-14 9:12 ` Li Feng
2009-07-14 9:40 ` Richard Guenther
2009-07-14 15:14 ` Sebastian Pop
2009-07-14 15:26 ` Richard Guenther
2009-07-14 16:03 ` Sebastian Pop
2009-07-14 16:09 ` Sebastian Pop
2009-07-14 21:34 ` Richard Guenther
2009-07-15 7:59 ` Li Feng
2009-07-15 11:02 ` Tobias Grosser
2009-07-15 11:26 ` Richard Guenther
2009-07-15 19:16 ` Tobias Grosser
2009-07-15 20:46 ` Richard Guenther
2009-07-15 20:49 ` Richard Guenther
[not found] ` <15137_1247690941_4A5E40BC_15137_586_1_84fc9c000907151348s41395cc5u6cfacb60cde78bfa@mail.gmail.com>
2009-07-15 23:16 ` Tobias Grosser [this message]
2009-07-16 8:39 ` Richard Guenther
2009-07-16 9:00 ` Li Feng
2009-07-16 9:16 ` Richard Guenther
2009-07-16 15:45 ` Daniel Berlin
2009-07-16 16:04 ` Sebastian Pop
2009-07-17 1:36 ` Li Feng
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