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From: Jakub Jelinek <jakub@redhat.com>
To: Erik Schnetter <schnetter@uni-tuebingen.de>
Cc: gcc@gcc.gnu.org
Subject: Re: Implementing real*16 in Fortran
Date: Sun, 03 Aug 2003 20:35:00 -0000	[thread overview]
Message-ID: <20030803185439.GR20507@sunsite.ms.mff.cuni.cz> (raw)
In-Reply-To: <200308031317.33934.schnetter@uni-tuebingen.de>

On Sun, Aug 03, 2003 at 01:17:19PM +0200, Erik Schnetter wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
> 
> I want to implement real*16 in Fortran.  For that I seem to need two 
> things:
> 
> (1) For run time libraries, I need a corresponding C type.  I think the 
> best thing would be to use long double for that, but it has to have a 
> sizeof of 16.  On i386, the option -m128bit-long-double does just this.  
> Is there a way to declare a type that does not need this option?  I 

I don't think IA-32/IA-64/amd64 TFmode (ieee_extended_128)
is what you're looking for. That's still the same thing as XFmode, but
padded to 16 bytes.
Doesn't Fortran mandate IEEE quad format (TFmode on sparc and a couple
of other platforms), ie. 1 bit sign, 15 bits exponent, 112+1 bits of
mantissa?

	Jakub

  reply	other threads:[~2003-08-03 18:54 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2003-08-03 12:57 Erik Schnetter
2003-08-03 20:35 ` Jakub Jelinek [this message]
2003-08-03 21:30   ` Erik Schnetter

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