* Question about unspec and canon_reg()
@ 2001-12-14 4:08 Marco Altieri
0 siblings, 0 replies; only message in thread
From: Marco Altieri @ 2001-12-14 4:08 UTC (permalink / raw)
To: gcc
I am working on a gcc porting for a DSP architecture.
It happens that, while performing cse pass, in function
canon_reg() gcc tries to substitute each pseudoreg
with its older reference.
The problem we have is that when a pseudoreg appears
as an element of the vector operand of an unspec rtx,
gcc performs substitution without checking the validity
of the resulting insn:
fmt = GET_RTX_FORMAT (code);
for (i = GET_RTX_LENGTH (code) - 1; i >= 0; i--)
{
register int j;
if (fmt[i] == 'e')
{
rtx new = canon_reg (XEXP (x, i), insn);
int insn_code;
/* If replacing pseudo with hard reg or vice versa, ensure the
insn remains valid. Likewise if the insn has MATCH_DUPs. */
if (insn != 0 && new != 0
&& GET_CODE (new) == REG && GET_CODE (XEXP (x, i)) == REG
&& (((REGNO (new) < FIRST_PSEUDO_REGISTER)
!= (REGNO (XEXP (x, i)) < FIRST_PSEUDO_REGISTER))
|| (insn_code = recog_memoized (insn)) < 0
|| insn_data[insn_code].n_dups > 0))
validate_change (insn, &XEXP (x, i), new, 1);
else
XEXP (x, i) = new;
}
else if (fmt[i] == 'E')
for (j = 0; j < XVECLEN (x, i); j++)
XVECEXP (x, i, j) = canon_reg (XVECEXP (x, i, j), insn);
//NO CHECK IS DONE HERE!
}
Thanks,
Marco Altieri
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