From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 13527 invoked by alias); 26 Jul 2005 23:43:03 -0000 Mailing-List: contact gcc-help@gcc.gnu.org; run by ezmlm Precedence: bulk List-Archive: List-Post: List-Help: Sender: gcc-owner@gcc.gnu.org Received: (qmail 13514 invoked by uid 22791); 26 Jul 2005 23:42:58 -0000 Received: from zproxy.gmail.com (HELO zproxy.gmail.com) (64.233.162.204) by sourceware.org (qpsmtpd/0.30-dev) with ESMTP; Tue, 26 Jul 2005 23:42:58 +0000 Received: by zproxy.gmail.com with SMTP id s1so35941nze for ; Tue, 26 Jul 2005 16:42:56 -0700 (PDT) Received: by 10.36.129.5 with SMTP id b5mr262164nzd; Tue, 26 Jul 2005 16:42:56 -0700 (PDT) Received: by 10.36.115.18 with HTTP; Tue, 26 Jul 2005 16:42:56 -0700 (PDT) Message-ID: <7326d8e40507261642df6bf5e@mail.gmail.com> Date: Tue, 26 Jul 2005 23:43:00 -0000 From: drizzle drizzle Reply-To: drizzle drizzle To: Daniel Berlin Subject: Re: Annotations in tree Cc: gcc@gcc.gnu.org In-Reply-To: <1122419430.7683.21.camel@linux.site> Mime-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Content-Disposition: inline References: <7326d8e405072613213c282bd7@mail.gmail.com> <20050726203123.GA4355@topo.toronto.redhat.com> <7326d8e4050726153954b9a5f0@mail.gmail.com> <1122419430.7683.21.camel@linux.site> X-SW-Source: 2005-07/txt/msg01113.txt.bz2 What doesnt exist very long - the references ?=20 At RTL level, I just want to insert a counter for each one of these. One alternative I saw is inserting a dummy functiion call. Would that work ? If so, for a given name, how do I create a corresponding function expression for it ? thanks for the answers=20 On 7/26/05, Daniel Berlin wrote: > On Tue, 2005-07-26 at 18:39 -0400, drizzle drizzle wrote: > > I am not sure if I unerstand ...can you elaborate please ? So what I > > need is if I identify say a reference a[i] inside a loop, I want to > > identify the corresponding RTL. >=20 > What are you trying to do at the RTL level with array references? > They don't last that long. >=20 >=20 >