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In-Reply-To: <20031209204037.906D84B412@berman.michael-chastain.com>
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Cc: gcc@gcc.gnu.org, Dale Johannesen <dalej@apple.com>
From: Dale Johannesen <dalej@apple.com>
Subject: Re: (printf) ("hello world\n");
Date: Tue, 09 Dec 2003 21:01:00 -0000
To: mec.gnu@mindspring.com (Michael Elizabeth Chastain)
X-SW-Source: 2003-12/txt/msg00597.txt.bz2


On Dec 9, 2003, at 12:40 PM, Michael Elizabeth Chastain wrote:

> I have a language lawyer question.
>
>   int main ()
>   {
>     (printf) ("hello world\n");
>     return 0;
>   }
>
> Is this a conforming C program?

c89 3.3.2.2:
"If the expression that precedes the parenthesized argument list in a 
function call
consists solely of an identifier, and if no declaration is visible for 
this identifier,
the identifier is implicitly declared exactly as if , in the innermost 
block containing
the function call, the declaration "extern int <identifier>();" 
appeared."

So the implicit declaration is not supposed to happen when the function 
identifier
is surrounded by parentheses, and this is not conforming.