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In-Reply-To: <43097A70.70108@lu.unisi.ch>
To: Paolo Bonzini <paolo.bonzini@lu.unisi.ch>
Cc: GCC Development <gcc@gcc.gnu.org>
MIME-Version: 1.0
Subject: Re: Question about merging two instructions.
From: Leehod Baruch <LEEHOD@il.ibm.com>
Message-ID: <OF6BB453A0.91AAF632-ONC2257065.004BFE98-C2257065.004E32C4@il.ibm.com>
Date: Mon, 22 Aug 2005 14:12:00 -0000
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X-SW-Source: 2005-08/txt/msg00590.txt.bz2

Paolo Bonzini <paolo.bonzini@lu.unisi.ch> wrote on 22/08/2005 10:10:40:
> > > I tried to use simplify_replace_rtx to replace any use of (reg r) 
with[in]
> > > the right-hand-side of the extension and simplify the result.
> 
> If he want to replace uses within the RHS of the extension, he should 
> pass SET_SRC (pat).  He may as well want to handle parallels, in which 
> case he should write a new function similar to this:

I think you misunderstood my original purpose. I did mean [with]
and not [in].
Let me explain again.

I have these two instructions:

(insn 1 0 2 0 (set (reg/v:Xmode r)
        (sign_extend:Xmode (op:Ymode (...))))
(insn 2 1 3 0 (set (LHS) (RHS)))

where:
1. Xmode > Ymode
2. RHS and/or LHS may contain: 
   (subreg:Ymode (reg/v:Xmode r) lowpart) and/or (reg/v:Xmode r).

Now I want to replace every *use* of (reg r) in insn 2 with the rhs of
insn 1 and simplify the result.  This is way the replacement may happen
in the LHS of insn 2.
Note that I don't want to replace any *def* and uses may appear in the 
LHS.

My plan was to use: replace_regs () to replace every use of (reg r)
with the a new pseudo register (because this is the only function that
I found that separates the uses from the defs) and then use
simplifiy_replace_rtx () to replace that new pseudo register with the rhs 
of insn 1 and simplify.

To make things even more complicated - insn 2 may be PARALLEL.

Maybe I should use simplify_rtx (replace_rtx (..))?
But it seem to me that simplify_rtx () doesn't deal with SET either.

Do you see a better way?

Thanks,
Leehod.