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To: Segher Boessenkool <segher@kernel.crashing.org>
Cc: "Joseph S. Myers" <jsm@polyomino.org.uk>,
	Michael Elizabeth Chastain <mec.gnu@mindspring.com>,
	Robert Dewar <dewar@gnat.com>, gcc@gcc.gnu.org,
	Eyal Lebedinsky <eyal@eyal.emu.id.au>
Subject: Re: (printf) ("hello world\n");
References: <20031209204037.906D84B412@berman.michael-chastain.com>
	<jmvfopy2un.fsf@desire.geoffk.org> <3FD6DD9B.E35C742@eyal.emu.id.au>
	<jeiskpxal1.fsf@sykes.suse.de> <3FD71140.2070506@gnat.com>
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From: Andreas Schwab <schwab@suse.de>
X-Yow: Just to have MORE FUN, I'll pretend I am JAMES CAGNEY and I am having
 a tense, UP-TIGHT EXPERIENCE!!
Date: Wed, 10 Dec 2003 15:55:00 -0000
In-Reply-To: <4F621C55-2B1A-11D8-8ABB-000A95A4DC02@kernel.crashing.org> (Segher
 Boessenkool's message of "Wed, 10 Dec 2003 15:08:20 +0100")
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Segher Boessenkool <segher@kernel.crashing.org> writes:

> On 10-dec-03, at 14:36, Joseph S. Myers wrote:
>> On Wed, 10 Dec 2003, Segher Boessenkool wrote:
>>> On 10-dec-03, at 13:27, Robert Dewar wrote:
>>>> Is it really true that the name printf is reserved? Is a C program not
>>>> allowed to define its own printf function (which might or might not be
>>>> varargs)? What's the story here?
>>>
>>> It is reserved only in translation units that have stdio.h #include'd.
>>
>> It is reserved (in a hosted environment) as an identifier with external
>> linkage regardless of what headers are included (7.1.3#1).
>
> That does not prevent you from declaring and defining your own
> printf() function (with a different prototype) though; it only requires
> that you make that function have external linkage.

Which requires that you declare it in the first place, otherwise it will
have implicitly external linkage.

Andreas.

-- 
Andreas Schwab, SuSE Labs, schwab@suse.de
SuSE Linux AG, Maxfeldstraße 5, 90409 Nürnberg, Germany
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"And now for something completely different."