From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 97066 invoked by alias); 15 Mar 2018 11:24:43 -0000 Mailing-List: contact gcc-help@gcc.gnu.org; run by ezmlm Precedence: bulk List-Id: List-Archive: List-Post: List-Help: Sender: gcc-owner@gcc.gnu.org Received: (qmail 96909 invoked by uid 89); 15 Mar 2018 11:24:22 -0000 Authentication-Results: sourceware.org; auth=none X-Virus-Found: No X-Spam-SWARE-Status: No, score=-1.9 required=5.0 tests=BAYES_00,SPF_PASS,TIME_LIMIT_EXCEEDED autolearn=unavailable version=3.3.2 spammy=H*UA:https, H*i:sk:CAKGfg-, H*i:sk:KA@mail, H*i:thZaSkA8gs0 X-HELO: mx2.suse.de Received: from mx2.suse.de (HELO mx2.suse.de) (195.135.220.15) by sourceware.org (qpsmtpd/0.93/v0.84-503-g423c35a) with ESMTP; Thu, 15 Mar 2018 11:24:05 +0000 Received: from relay1.suse.de (charybdis-ext.suse.de [195.135.220.254]) by mx2.suse.de (Postfix) with ESMTP id AC7E9ABA3; Thu, 15 Mar 2018 11:24:03 +0000 (UTC) From: Martin Jambor To: Gaurav Ahuja , gcc@gcc.gnu.org Cc: Subject: Re: GSoC In-Reply-To: References: User-Agent: Notmuch/0.25.1 (https://notmuchmail.org) Emacs/25.3.1 (x86_64-suse-linux-gnu) Date: Thu, 15 Mar 2018 11:24:00 -0000 Message-ID: MIME-Version: 1.0 Content-Type: text/plain X-IsSubscribed: yes X-SW-Source: 2018-03/txt/msg00170.txt.bz2 Hello Gurav, On Thu, Mar 15 2018, Gaurav Ahuja wrote: > I had a query, while choosing project for GSoC. Actually I'm > contributing to GCC for the first time, and I am not sure about what > is expected of me. > > So, can you please explain me about , what GCC organisation expects me > to do, like detect bugs, or add a new feature ,etc.? I am not sure I understand your question. GCC as an GSoC organization does not give prospective students any tasks they need to complete before applying. However, it is a good idea to at least check out, build and test the compiler suite before you apply for a project with us. See the information at https://gcc.gnu.org/wiki/SummerOfCode#Before_you_apply and generally speaking the entire wiki page on GSoC for what to do. Martin