[Bug c++/12213] operator() does not work

["cvs-commit at gcc dot gnu.org" <sourceware-bugzilla@sourceware.org>]

https://sourceware.org/bugzilla/show_bug.cgi?id=12213

--- Comment #1 from Sourceware Commits <cvs-commit at gcc dot gnu.org> ---
The master branch has been updated by Hannes Domani <ssbssa@sourceware.org>:

https://sourceware.org/git/gitweb.cgi?p=binutils-gdb.git;h=292b9a302933418abcb8b76b23e83af8028c659a

commit 292b9a302933418abcb8b76b23e83af8028c659a
Author: Hannes Domani <ssbssa@yahoo.de>
Date:   Wed Jun 12 15:24:02 2024 +0200

    Allow calling of user-defined function call operators

    Currently it's not possible to call user-defined function call
    operators, at least not without specifying operator() directly:
    ```
    (gdb) l 1
    1       struct S {
    2         int operator() (int x) { return x + 5; }
    3       };
    4
    5       int main () {
    6         S s;
    7
    8         return s(23);
    9       }
    (gdb) p s(10)
    Invalid data type for function to be called.
    (gdb) p s.operator()(10)
    $1 = 15
    ```

    This now looks if an user-defined call operator is available when
    trying to 'call' a struct value, and calls it instead, making this
    possible:
    ```
    (gdb) p s(10)
    $1 = 15
    ```

    The change in operation::evaluate_funcall is to make sure the type
    fields are only used for function types, only they use them as the
    argument types.

    Bug: https://sourceware.org/bugzilla/show_bug.cgi?id=12213
    Approved-By: Tom Tromey <tom@tromey.com>

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