[Bug c++/12213] New: operator() does not work

[Bug c++/12213] New: operator() does not work

[tromey at redhat dot com]

http://sourceware.org/bugzilla/show_bug.cgi?id=12213

           Summary: operator() does not work
           Product: gdb
           Version: HEAD
            Status: NEW
          Severity: normal
          Priority: P2
         Component: c++
        AssignedTo: unassigned@sourceware.org
        ReportedBy: tromey@redhat.com


C++ operator() overloading does not work in gdb.
Try this program:

struct S {
  int operator() (int x) { return x + 5; }
};

int main () {
  S s;

  return s(23);
}


When I try "print s(23)", I get:

(gdb) p s(23)
Invalid data type for function to be called.

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[Bug c++/12213] operator() does not work

[tromey at redhat dot com]

https://sourceware.org/bugzilla/show_bug.cgi?id=12213

Tom Tromey <tromey at redhat dot com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Blocks|                            |16106

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[Bug c++/12213] operator() does not work

[ssbssa at sourceware dot org]

https://sourceware.org/bugzilla/show_bug.cgi?id=12213

Hannes Domani <ssbssa at sourceware dot org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |ssbssa at sourceware dot org

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[Bug c++/12213] operator() does not work

[cvs-commit at gcc dot gnu.org]

https://sourceware.org/bugzilla/show_bug.cgi?id=12213

--- Comment #1 from Sourceware Commits <cvs-commit at gcc dot gnu.org> ---
The master branch has been updated by Hannes Domani <ssbssa@sourceware.org>:

https://sourceware.org/git/gitweb.cgi?p=binutils-gdb.git;h=292b9a302933418abcb8b76b23e83af8028c659a

commit 292b9a302933418abcb8b76b23e83af8028c659a
Author: Hannes Domani <ssbssa@yahoo.de>
Date:   Wed Jun 12 15:24:02 2024 +0200

    Allow calling of user-defined function call operators

    Currently it's not possible to call user-defined function call
    operators, at least not without specifying operator() directly:
    ```
    (gdb) l 1
    1       struct S {
    2         int operator() (int x) { return x + 5; }
    3       };
    4
    5       int main () {
    6         S s;
    7
    8         return s(23);
    9       }
    (gdb) p s(10)
    Invalid data type for function to be called.
    (gdb) p s.operator()(10)
    $1 = 15
    ```

    This now looks if an user-defined call operator is available when
    trying to 'call' a struct value, and calls it instead, making this
    possible:
    ```
    (gdb) p s(10)
    $1 = 15
    ```

    The change in operation::evaluate_funcall is to make sure the type
    fields are only used for function types, only they use them as the
    argument types.

    Bug: https://sourceware.org/bugzilla/show_bug.cgi?id=12213
    Approved-By: Tom Tromey <tom@tromey.com>

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[Bug c++/12213] operator() does not work

[ssbssa at sourceware dot org]

https://sourceware.org/bugzilla/show_bug.cgi?id=12213

Hannes Domani <ssbssa at sourceware dot org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
   Target Milestone|---                         |16.1
         Resolution|---                         |FIXED
             Status|NEW                         |RESOLVED

--- Comment #2 from Hannes Domani <ssbssa at sourceware dot org> ---
Fixed.

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