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From: "saugustine at google dot com" <sourceware-bugzilla@sourceware.org>
To: gdb-prs@sourceware.org
Subject: [Bug gdb/12883] New: watchpoint on variable in function scope
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http://sourceware.org/bugzilla/show_bug.cgi?id=12883

           Summary: watchpoint on variable in function scope
           Product: gdb
           Version: unknown
            Status: NEW
          Severity: normal
          Priority: P2
         Component: gdb
        AssignedTo: unassigned@sourceware.org
        ReportedBy: saugustine@google.com


Given the following program:

void foo() {
   static int i=0;
   ++i;
}
int main(int argc, char **argv) {
   foo();
   return 0;
}

Setting a watchpoint on foo::i works if the program is compiled as a C program,
but fails if the program is compiled as C++.

Not sure what the proper behavior is, but probably should be consistent from C
to C++.

$ gcc ~/bar.c -g
$ ./gdb ./a.out
GNU gdb (GDB) 7.2.90.20110513-cvs
...
(gdb) watch foo::i
Watchpoint 1: foo::i
(gdb) run
Starting program: ./a.out
Hardware watchpoint 1: foo::i

Old value = 0
New value = 1
foo () at /home/saugustine/bar.c:4
4       }

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