[Bug python/16020] New: Print trailing nul in c++ std::string?

["dje at google dot com" <sourceware-bugzilla@sourceware.org>]

https://sourceware.org/bugzilla/show_bug.cgi?id=16020

            Bug ID: 16020
           Summary: Print trailing nul in c++ std::string?
           Product: gdb
           Version: HEAD
            Status: NEW
          Severity: normal
          Priority: P2
         Component: python
          Assignee: unassigned at sourceware dot org
          Reporter: dje at google dot com

Feel free to move this to libstdc++ if warranted, but most of the
pretty-printing of std strings is in gdb so I figured I'd start here.
[Whether printing of lazy strings correctly falls under category python or c++
or whatever ... feel free to correct that too.]

Consider:

#include <string>
#include <iostream>

using namespace std;

int
main (void)
{
  static const char foo[] = "abc";
  string foo0_str (foo, sizeof (foo));
  string foo_str (foo, sizeof (foo) - 1);

  cout << "foo0_str: \"" << foo0_str << "\"\n";
  cout << "foo_str: \"" << foo_str << "\"\n";

  return 0;
}

Here is the output:

$ ./trailing-nul.x64
foo0_str: "abc^@"
foo_str: "abc"

However, the trailing nul in foo0_str is not included in pretty-printed output:

(gdb) p foo0_str
$1 = "abc"
(gdb) p foo_str
$2 = "abc"

Bug?

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