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From: "blarsen at redhat dot com" <sourceware-bugzilla@sourceware.org> To: gdb-prs@sourceware.org Subject: [Bug c++/29602] New: cant use typedef class name of a baseclass Date: Thu, 22 Sep 2022 16:06:29 +0000 [thread overview] Message-ID: <bug-29602-4717@http.sourceware.org/bugzilla/> (raw) https://sourceware.org/bugzilla/show_bug.cgi?id=29602 Bug ID: 29602 Summary: cant use typedef class name of a baseclass Product: gdb Version: HEAD Status: NEW Severity: normal Priority: P2 Component: c++ Assignee: unassigned at sourceware dot org Reporter: blarsen at redhat dot com Target Milestone: --- Consider the following code: ``` class base{ public: int x; }; typedef base tbase; class derived: public base{ public: int y; }; int main(){ derived der; der.y = 0; der.tbase::x = 1; return der.tbase::x; } ``` g++ is able to compile it with no problems, but in GDB I get: (gdb) 17 return der.tbase::x; (gdb) print der.base::x $1 = 1 (gdb) print der.tbase::x A syntax error in expression, near `'. GDB should be able to resolve the typedef in the user expression and find the correct member. -- You are receiving this mail because: You are on the CC list for the bug.
next reply other threads:[~2022-09-22 16:06 UTC|newest] Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top 2022-09-22 16:06 blarsen at redhat dot com [this message] 2022-09-27 18:12 ` [Bug c++/29602] " keiths at redhat dot com 2022-10-03 16:04 ` blarsen at redhat dot com
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