[Bug c++/29918] New: GDB cannot step or break into template functions compiled with g++ -Og

["vimacs.hacks at gmail dot com" <sourceware-bugzilla@sourceware.org>]

https://sourceware.org/bugzilla/show_bug.cgi?id=29918

            Bug ID: 29918
           Summary: GDB cannot step or break into template functions
                    compiled with g++ -Og
           Product: gdb
           Version: 12.1
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: c++
          Assignee: unassigned at sourceware dot org
          Reporter: vimacs.hacks at gmail dot com
  Target Milestone: ---

This is another issue posted on
https://sourceware.org/pipermail/gdb/2022-November/050431.html

For the following C++ code, I find that GDB (both 12.1 and
gdb-13-branchpoint-5-g2a517ca94d3) cannot step or break into C++ template
function t0<int> compiled with g++ -Og (GCC version 12.2.0), while LLDB from
LLVM 14.0.6 can step into this function:

template <typename T = int>
int t0(int n)
{
     int sum = 0;
     for (int i = 0; i < n; ++i) {
         sum += i * i;
     }
     return sum;
}

int t1(int n)
{
     int sum = 0;
     for (int i = 0; i < n; ++i) {
         sum += i * i;
     }
     return sum;
}

int main()
{
     int a = t0(5);
     int b = t1(5);
     return a + b;
}

The behavior in GDB looks like this:

Breakpoint 1, main () at template_func.cc:21
21      {
(gdb) n
22           int a = t0(5);
(gdb) s
t0<int> (n=n@entry=5) at template_func.cc:2
2       int t0(int n)
(gdb) 
main () at template_func.cc:23
23           int b = t1(5);
(gdb) 

The assembly output of "g++-g -Og" and "g++ -g -O0" are both attached in the
attachment of the following comments, which can be assembled and reproduce this
issue.

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