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From: "jsberg at bnl dot gov" <sourceware-bugzilla@sourceware.org>
To: gdb-prs@sourceware.org
Subject: [Bug fortran/29949] New: Fortran type members with names identical to global identifiers can't be examined
Date: Fri, 30 Dec 2022 18:15:51 +0000	[thread overview]
Message-ID: <bug-29949-4717@http.sourceware.org/bugzilla/> (raw)

https://sourceware.org/bugzilla/show_bug.cgi?id=29949

            Bug ID: 29949
           Summary: Fortran type members with names identical to global
                    identifiers can't be examined
           Product: gdb
           Version: 12.1
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: fortran
          Assignee: unassigned at sourceware dot org
          Reporter: jsberg at bnl dot gov
  Target Milestone: ---

Created attachment 14543
  --> https://sourceware.org/bugzilla/attachment.cgi?id=14543&action=edit
Fortran source code for test case

Compile the test case shown, and try to examine the members of t0 in gdb. The x
member can be printed just fine, but the members t and floor both fail with a
syntax error, I speculate because t is the type name and floor is the name of a
global function. gdb log:

Breakpoint 1, p221230aa () at 221230aa.f90:9
9         write(*,*) t0%t,t0%x,t0%floor
(gdb) p t0%t
A syntax error in expression, near `t'.
(gdb) p t0%x
$1 = 4
(gdb) p t0%floor
A syntax error in expression, near `floor'.

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                 reply	other threads:[~2022-12-30 18:16 UTC|newest]

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