Re: ptype of prototype of a funtion

["Muthukumar" <kmuthu_linux@HotPOP.com>]

>>
> gdb>ptype fun
> type = int ()
>
> But 'ptype fun' just displays the return type followed by paranthesis.
>
> Also,
>
> gdb>ptype fun()
> type = int
> What a great! the paranthesis is missing.

You can get also the function information using thr "whatis" command too.
as .,
whatis fun (or) whatis fun()

> But I am unable to get the parameter type.
> Is there really a way to find the parameter type ?

If you are attempting to know about the function parameters then they are only known to the function loop only.
not to the main function.Because they may be local to the function not as global.
At that time you have to get the function parameter informations by going into the function and put the command
ptype or whatis for the particular parameter type.

For example:
main()

If you get the information with ptype then
gdb> ptype main
type = int ()

If you change the code as
/* Global variables */
int argc;
char argv[];
main(argc,argv)

If you get the information with ptype / whatis then
gdb> ptype main
type = int (int, int)

>
> Thanks,
> Murugesan
>


Regards,
Muthukumar.

===========================================================================================
>
> ----- Original Message -----
> From: Daniel Jacobowitz
> To: murugesan
> Cc: gdb@sources.redhat.com
> Sent: Friday, March 12, 2004 9:09 PM
> Subject: Re: ptype of prototype of a funtion
>
>
> On Fri, Mar 12, 2004 at 01:23:59PM +0530, murugesan wrote:
> > Hello all,
> >     ptype fun(NULL,NULL)
> > This gives me the return type of the function fun
> >     Is there a way to get  the prototype of a function i gdb.
> >
> > I don't know the type of the parameters of fun which can have the value
> > NULL. [ (void*)0 ]
> >
> > thanks in advance for the help.
>
> How about 'ptype fun'?
>
> --
> Daniel Jacobowitz
> MontaVista Software                         Debian GNU/Linux Developer
>
>