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From: Thomas Covenant <null_geodesic@yahoo.com>
To: gdb@sources.redhat.com
Subject: When do watchpoints go out of scope?
Date: Sun, 25 Sep 2005 14:37:00 -0000	[thread overview]
Message-ID: <20050925143734.65016.qmail@web34809.mail.mud.yahoo.com> (raw)

Consider this program:

1 int main(void)
2 {
3    {
4       int i = 2;
5       printf("i is %d.\n", i);
6       i = 3;
7       printf("i is %d.\n", i);
8    }
9    // lots more code
     ...
90   return 0;
100 }

The variable i goes in scope at line 4, out of scope
at line 8.

If I set:

   watch i

at line 4, I would assume the watchpoint would be
deleted at line 8, since i is no longer in scope.

Yet, the watchpoint persists at line 9 and beyond,
even though i is no longer in scope.

Why is this?  And what exactly is the watchpoint
watching when i is out of scope?

Thanks!


		
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Yahoo! Mail - PC Magazine Editors' Choice 2005 
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             reply	other threads:[~2005-09-25 14:37 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2005-09-25 14:37 Thomas Covenant [this message]
2005-09-25 17:25 ` Daniel Jacobowitz
2005-10-10 23:21   ` Ross Morley

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