Re: gdb cannot understand some type with STL

[Daniel Jacobowitz <drow@false.org>]

On Sat, Dec 22, 2007 at 01:24:16PM +0800, jian shen wrote:
> testcase 2:
> 
> ----- stl.cpp -----
> #include <list>
> #include <map>
> #include <string>
> 
> int main()
> {
>   std::list<int> l;
>   l.push_back(1);
>   l.push_back(2);
> 
>   std::map<std::string, int> m;
>   m["a1"] = 1;
>   m["a2"] = 2;
> }
> ----- stl.cpp -----
> 
> (gdb) whatis std::list<int>
> No symbol "list<int>" in namespace "std".

What does "whatis l" print?  I believe this problem is because GDB
does not know about default template parameters.

  template<typename _Tp, typename _Alloc = std::allocator<_Tp> >
    class list : protected _List_base<_Tp, _Alloc>

It's going to be a std::list<int, std::allocator<int> > or something
like that.

This is fixable, but it would require changes to both GCC and GDB that
no one has worked on yet.

> (gdb) whatis std::list<int>*
> A syntax error in expression, near `'.

This looks like a bug in GDB, in the c-exp.y parser.

-- 
Daniel Jacobowitz
CodeSourcery