gdb steps into glibc functions

[Marc Gonzalez-Sigler <marc.gonzalez-sigler@inria.fr>]

Hi all,

I have the following system:

$ uname -a
Linux ikaria 2.4.16 #1 Wed Jan 9 15:04:38 CET 2002 i686 unknown

$ gdb -v
GNU gdb 5.0rh-5 Red Hat Linux 7.1
Copyright 2001 Free Software Foundation, Inc.
GDB is free software, covered by the GNU General Public License, and 
you are
welcome to change it and/or distribute copies of it under certain 
conditions.
Type "show copying" to see the conditions.
There is absolutely no warranty for GDB.  Type "show warranty" for 
details.
This GDB was configured as "i386-redhat-linux".

When I use the step command in gdb, it seems that gdb tries to step 
into glibc functions.


325         a2b = (strcmp (progname, "ir_a2b") == 0);
(gdb) step
strcmp (p1=0xbfffface "ir_b2a", p2=0x80ed99f "ir_a2b") at 
../sysdeps/generic/strcmp.c:33
33      ../sysdeps/generic/strcmp.c: No such file or directory.
         in ../sysdeps/generic/strcmp.c
Current language:  auto; currently c


This does not happen on my home computer: even when I use the step 
command, gdb steps over glibc calls.

Does it mean that glibc was compiled with debugging information on 
this Redhat system? And gdb complains because it cannot find the 
source code?

If this is the case, then I would obtain the behavior I am used to 
as soon as I use a version of glibc which was compiled without 
debugging information, no? Could I just strip the library?

One last question: once I enter a function, say, strcmp(), is finish 
the correct command to jump out of the function?

Marc