Re: sizeof

[Russell Shaw <rjshaw@netspace.net.au>]

Andreas Schwab wrote:
>On Mai 11 2022, Russell Shaw wrote:
>
>> On 10/5/22 5:22 pm, Andreas Schwab wrote:
>>> On Mai 10 2022, Russell Shaw wrote:
>>>
>>>>> Andreas Schwab wrote:
>>>>> On Mai 09 2022, Russell Shaw wrote:
>>>>>
>>>>>> sizeof(int()) should transform to sizeof(int (*)()) according to the 
C++20 standard.
>>>>>
>>>>> No, see [expr.sizeof] #3.
>>>>
>>>> What does "[expr.sizeof] #3" refer to ?
>>> Paragrph #3 in section [expr.sizeof].
>>>      "The lvalue-to-rvalue (7.3.1), array-to-pointer (7.3.2), and
>>>      function-to-pointer (7.3.3) standard conversions are not applied to
>>>      the operand of sizeof."
>>
>> "Standard conversions" are only applied to expressions, not type-id (which
>> is an abstract declarator syntax).
>
>So what's the chapter and verse for your claim?

It is not spelt out, but implied from the context.

Clearly, the standard conversions are only a meaningful concept for expressions.

"int()" is not an expression, but a type-id for a function pointer "int(*)()"

so "sizeof(int())" == "size of ptr to function"

unary-expression :
   ...
   sizeof unary-expression
   sizeof ( type-id )