From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 31654 invoked by alias); 5 Jun 2012 09:30:09 -0000 Received: (qmail 31638 invoked by uid 22791); 5 Jun 2012 09:30:08 -0000 X-SWARE-Spam-Status: No, hits=-2.5 required=5.0 tests=AWL,BAYES_00,DKIM_SIGNED,DKIM_VALID,DKIM_VALID_AU,FREEMAIL_FROM,KHOP_RCVD_TRUST,RCVD_IN_DNSWL_LOW,RCVD_IN_HOSTKARMA_YE X-Spam-Check-By: sourceware.org Received: from mail-gg0-f169.google.com (HELO mail-gg0-f169.google.com) (209.85.161.169) by sourceware.org (qpsmtpd/0.43rc1) with ESMTP; Tue, 05 Jun 2012 09:29:56 +0000 Received: by ggm4 with SMTP id 4so4383704ggm.0 for ; Tue, 05 Jun 2012 02:29:56 -0700 (PDT) MIME-Version: 1.0 Received: by 10.50.197.200 with SMTP id iw8mr1570908igc.46.1338888595750; Tue, 05 Jun 2012 02:29:55 -0700 (PDT) Received: by 10.64.95.97 with HTTP; Tue, 5 Jun 2012 02:29:55 -0700 (PDT) Date: Tue, 05 Jun 2012 09:30:00 -0000 Message-ID: Subject: how can gdb get the GDTR value ? Is there one command for this? From: Tom Frank To: gdb@sourceware.org Content-Type: text/plain; charset=ISO-8859-1 X-IsSubscribed: yes Mailing-List: contact gdb-help@sourceware.org; run by ezmlm Precedence: bulk List-Id: List-Subscribe: List-Archive: List-Post: List-Help: , Sender: gdb-owner@sourceware.org X-SW-Source: 2012-06/txt/msg00028.txt.bz2 how can gdb get the GDTR value ? Is there one command for this?