在 2020/8/11 下午9:55, Nathan Sidwell 写道:
> 
> I agree, it's the way I use auto.  I particularly like the
>    auto *foo = expr;
> idiom, when you're getting a pointer, but the type of the pointee is clear.  It informs how you use 'foo'.
> 
> 

Personally I dislike this syntax. Pointers are objects, and `auto foo = expr;` should suffice. What if the type of `expr` is
`unique_ptr<T>` or `optional<T>`? The ptr-operator just can't exist there. So why the differentiation?

`auto& foo = ...` and `const auto& foo = ...` are necessary to indicate that the entity being declared is a reference (and
is not an object), while `auto*` doesn't make much sense, as I discourage plain pointers in my projects.



-- 
Best regards,
LH_Mouse