* Differences between Gold-produced gdb-index and GDB-produced gdb-index
@ 2011-10-05 19:07 Sterling Augustine
2011-10-05 20:29 ` Tom Tromey
0 siblings, 1 reply; 2+ messages in thread
From: Sterling Augustine @ 2011-10-05 19:07 UTC (permalink / raw)
To: gdb
[Resend now that tromey is back.]
Hi All,
gdb_index handles enumerator names inconsistently. It includes the
enum's name as part of the enumerator name, but only when it is
declared inside a namespace. When outside of a namespace, it leaves
the enumerator name out:
enum A { A_A };
enum A a = A_A;
namespace foo
{
enum B { B_B };
enum B b = B_B;
};
int main() {return 0;}
For this testcase, gdb index will include (among others):
A_A
foo::B::B_B
That seems wrong to me. Which is right? FWIW, Gold includes the enum
name in both cases.
Sterling
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: Differences between Gold-produced gdb-index and GDB-produced gdb-index
2011-10-05 19:07 Differences between Gold-produced gdb-index and GDB-produced gdb-index Sterling Augustine
@ 2011-10-05 20:29 ` Tom Tromey
0 siblings, 0 replies; 2+ messages in thread
From: Tom Tromey @ 2011-10-05 20:29 UTC (permalink / raw)
To: Sterling Augustine; +Cc: gdb
>>>>> "Sterling" == Sterling Augustine <saugustine@google.com> writes:
Sterling> [Resend now that tromey is back.]
I just sent a reply a few minutes ago :-)
Maybe I was confused then though.
Sterling> A_A
Sterling> foo::B::B_B
Sterling> That seems wrong to me. Which is right? FWIW, Gold includes the enum
Sterling> name in both cases.
I think the right answer is A_A and foo::B_B.
I am not completely positive.
I think what you'd have to do is dig into gdb to see what is the right
answer for expression parsing, symbol lookup, etc; then make sure that
gdb actually uses this in its symbol tables. The index has to reflect
whatever gdb decides; but this does not necessarily imply that gdb is
presently correct.
Tom
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2011-10-05 19:07 Differences between Gold-produced gdb-index and GDB-produced gdb-index Sterling Augustine
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