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From: "fweimer at redhat dot com" <sourceware-bugzilla@sourceware.org>
To: glibc-bugs-regex@sourceware.org
Subject: [Bug regex/18040] use-after-free in regexec/get_subexp
Date: Thu, 19 Mar 2015 14:53:00 -0000 [thread overview]
Message-ID: <bug-18040-132-XHBp1jYWva@http.sourceware.org/bugzilla/> (raw)
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https://sourceware.org/bugzilla/show_bug.cgi?id=18040
Florian Weimer <fweimer at redhat dot com> changed:
What |Removed |Added
----------------------------------------------------------------------------
CC| |fweimer at redhat dot com
--- Comment #1 from Florian Weimer <fweimer at redhat dot com> ---
Is it possible to trigger this without REG_EXTENDED and a back reference?
(“\1” in an ERE makes behavior undefined according to POSIX.)
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>From glibc-bugs-regex-return-677-listarch-glibc-bugs-regex=sources.redhat.com@sourceware.org Thu Mar 19 15:54:32 2015
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From: "konstantin.s.serebryany at gmail dot com" <sourceware-bugzilla@sourceware.org>
To: glibc-bugs-regex@sourceware.org
Subject: [Bug regex/18040] use-after-free in regexec/get_subexp
Date: Thu, 19 Mar 2015 15:54:00 -0000
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--- Comment #2 from Kostya Serebryany <konstantin.s.serebryany at gmail dot com> ---
(In reply to Florian Weimer from comment #1)
> Is it possible to trigger this without REG_EXTENDED and a back reference?
>
> (“\1” in an ERE makes behavior undefined according to POSIX.)
I don't think I've seen this w/o REG_EXTENDED, but let me re-run the fuzzer
with cflags=0
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>From glibc-bugs-regex-return-678-listarch-glibc-bugs-regex=sources.redhat.com@sourceware.org Thu Mar 19 16:17:25 2015
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From: "konstantin.s.serebryany at gmail dot com" <sourceware-bugzilla@sourceware.org>
To: glibc-bugs-regex@sourceware.org
Subject: [Bug regex/18037] infinite recursion (stack overflow) in regexec.c (sift_states_bkref->sift_states_backward->update_cur_sifted_state)
Date: Thu, 19 Mar 2015 16:17:00 -0000
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--- Comment #1 from Kostya Serebryany <konstantin.s.serebryany at gmail dot com> ---
Happens also without REG_EXTENDED:
#include <regex.h>
int main() {
regex_t r;
if (!regcomp(&r, "^9*\\(\\)\\1\\+\\+", 0))
regexec(&r, "foo.*bar", 0, 0, 0);
}
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next prev parent reply other threads:[~2015-03-19 14:53 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2015-02-26 21:31 [Bug regex/18040] New: " konstantin.s.serebryany at gmail dot com
2015-03-19 14:53 ` fweimer at redhat dot com [this message]
2015-03-19 16:20 ` [Bug regex/18040] " konstantin.s.serebryany at gmail dot com
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