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* [Bug math/3406] New: expf(x) gives infinity where correctly rounded result is finite
@ 2006-10-22  0:22 myles at peakstreaminc dot com
  2006-10-22  0:26 ` [Bug math/3406] " myles at peakstreaminc dot com
                   ` (2 more replies)
  0 siblings, 3 replies; 4+ messages in thread
From: myles at peakstreaminc dot com @ 2006-10-22  0:22 UTC (permalink / raw)
  To: glibc-bugs

glibc-2.3.4-2.19
gcc version 3.4.5 20051201 (Red Hat 3.4.5-2)

The attached sample program takes expf(x) and float(exp(x)) for a number x 
such that the exponential is ALMOST +INF in 32-bit floating point. expf(x) 
returns (incorrectly) INF, where float(exp(x)) is finite.

-- 
           Summary: expf(x) gives infinity where correctly rounded result is
                    finite
           Product: glibc
           Version: 2.3.4
            Status: NEW
          Severity: minor
          Priority: P2
         Component: math
        AssignedTo: aj at suse dot de
        ReportedBy: myles at peakstreaminc dot com
                CC: glibc-bugs at sources dot redhat dot com
  GCC host triplet: 2.6.9-34.ELsmp


http://sourceware.org/bugzilla/show_bug.cgi?id=3406

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^ permalink raw reply	[flat|nested] 4+ messages in thread

end of thread, other threads:[~2008-05-11 17:50 UTC | newest]

Thread overview: 4+ messages (download: mbox.gz / follow: Atom feed)
-- links below jump to the message on this page --
2006-10-22  0:22 [Bug math/3406] New: expf(x) gives infinity where correctly rounded result is finite myles at peakstreaminc dot com
2006-10-22  0:26 ` [Bug math/3406] " myles at peakstreaminc dot com
2008-02-11 20:52 ` jsm28 at gcc dot gnu dot org
2008-05-11 17:50 ` drepper at redhat dot com

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