From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 28196 invoked by alias); 10 Jan 2005 10:00:06 -0000 Mailing-List: contact gsl-discuss-help@sources.redhat.com; run by ezmlm Precedence: bulk List-Subscribe: List-Archive: List-Post: List-Help: , Sender: gsl-discuss-owner@sources.redhat.com Received: (qmail 25237 invoked from network); 7 Jan 2005 18:51:37 -0000 Message-ID: <41DEDA36.5020403@physik.hu-berlin.de> Date: Mon, 10 Jan 2005 10:00:00 -0000 From: Axel Hutt User-Agent: Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.7.3) Gecko/20040913 MIME-Version: 1.0 To: Przemyslaw Sliwa Cc: gsl-discuss@sources.redhat.com Subject: Re: Integrals References: In-Reply-To: Content-Type: text/plain; charset=us-ascii; format=flowed Content-Transfer-Encoding: 7bit X-SW-Source: 2005-q1/txt/msg00049.txt.bz2 Przemyslaw Sliwa wrote: >Can you tell me how you got this? > >I have not worked with complex valued functions. Thanks > >Przemyslaw > > > oh, maybe I was wrong, since I have interpreted the 1 as an i. If the exponent is real, means \phi, k and f are real functions, then the expression is purely imaginary and the real part is zero. Maybe you pass some more information about these functions. Axel