From: Chuah Teong Leong <teongleong@gmail.com>
To: kawa@sourceware.org
Subject: numArgs of a lambda procedure
Date: Sun, 12 Aug 2012 07:10:00 -0000 [thread overview]
Message-ID: <CAHxu6d-6HAa3X435f9gxadhBSvvNscvWo3uFSuRrCzXnHDROQg@mail.gmail.com> (raw)
Is there a simple way to get the number of required arguments from a
procedure object?
I tried the following
(define lamb0 (lambda () #f)
(define lamb1 (lambda (a) #f)
(define lamb2 (lambda (a b) #f)
(define lamb3 (lambda (a b c) #f)
(define lamb4 (lambda (a b c d) #f)
(display lamb0:numArgs)(newline)
(display lamb1:numArgs)(newline)
(display lamb2:numArgs)(newline)
(display lamb3:numArgs)(newline)
(display lamb4:numArgs)(newline)
0
4097
8094
12291
16388
Through this i can just match the value for 0 to 4 but I'm thinking
there must be a more orthodox means to do this.
Is there something I can do like
(procedure-property lamb0 'num-args)
to get the number of arguments?
Thank you in advance
next reply other threads:[~2012-08-12 7:10 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2012-08-12 7:10 Chuah Teong Leong [this message]
2012-08-12 7:22 ` Per Bothner
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