Compare two directories, architecture only

Compare two directories, architecture only

[Fergus]

Is there an easy way to compare two directories for content (names only 
of subdirectories and files, not their identical content).
(1) "diff" compares the content of files: too strong a comparison;
(2) Could "find" both directories and then compare output, but this will 
list the entire content under any non-matching subdirectories, when all 
I need is the fact of the non-match.
(i.e. I need
diff -rq d1 d2 | sed ' /^Files /d'    OR    diff -rq d1 d2 | grep '^Only'
without the scrutiny of file content that diff provides.)
Thank you!
Fergus

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Re: Compare two directories, architecture only

[marco atzeri]

On 3/29/2012 11:25 AM, Fergus wrote:
> Is there an easy way to compare two directories for content (names only
> of subdirectories and files, not their identical content).
> (1) "diff" compares the content of files: too strong a comparison;
> (2) Could "find" both directories and then compare output, but this will
> list the entire content under any non-matching subdirectories, when all
> I need is the fact of the non-match.
> (i.e. I need
> diff -rq d1 d2 | sed ' /^Files /d' OR diff -rq d1 d2 | grep '^Only'
> without the scrutiny of file content that diff provides.)
> Thank you!
> Fergus

not clear what are you looking for, just if the two trees are equal or
also the list of the differences (missing files) ?

cd dir1 ; find . -type f > /tmp/list1
cd dir2 ; find . -type f > /tmp/list2

then or
cmp /tmp/list1 /tmp/list2
or
diff -uN /tmp/list1 /tmp/list2

Regards
Marco






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Re: Compare two directories, architecture only

[Andrey Repin]

Greetings, Fergus!

> Is there an easy way to compare two directories for content (names only 
> of subdirectories and files, not their identical content).

What you want it for? If you only need it for your own convenience, you can
use compare tool included in file managers like Wincommander or Far Manager.

> (1) "diff" compares the content of files: too strong a comparison;
> (2) Could "find" both directories and then compare output, but this will 
> list the entire content under any non-matching subdirectories, when all 
> I need is the fact of the non-match.
> (i.e. I need
> diff -rq d1 d2 | sed ' /^Files /d'    OR    diff -rq d1 d2 | grep '^Only'
> without the scrutiny of file content that diff provides.)


--
WBR,
Andrey Repin (anrdaemon@freemail.ru) 30.03.2012, <20:54>

Sorry for my terrible english...


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Re: Compare two directories, architecture only

[Earnie Boyd]

On Fri, Mar 30, 2012 at 12:55 PM, Andrey Repin wrote:
> Greetings, Fergus!
>
>> Is there an easy way to compare two directories for content (names only
>> of subdirectories and files, not their identical content).

ls -1 dir1 > /tmp/dir1.out && ls -1 dir2 > /tmp/dir2.out && diff -u
/tmp/dir1.out /tmp/dir2.out

>
> What you want it for?

Who cares?  This was a simple question that has a simple answer.
Fergus will let you know if it isn't what he wanted. ;D

-- 
Earnie
-- https://sites.google.com/site/earnieboyd

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