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* [Bug c++/110752] New: decltype in lambda loses const qualifier unless lambda is mutable
@ 2023-07-20 13:57 jzwinck at gmail dot com
  2023-11-10 16:12 ` [Bug c++/110752] " ppalka at gcc dot gnu.org
  0 siblings, 1 reply; 2+ messages in thread
From: jzwinck at gmail dot com @ 2023-07-20 13:57 UTC (permalink / raw)
  To: gcc-bugs

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=110752

            Bug ID: 110752
           Summary: decltype in lambda loses const qualifier unless lambda
                    is mutable
           Product: gcc
           Version: 13.1.0
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
          Assignee: unassigned at gcc dot gnu.org
          Reporter: jzwinck at gmail dot com
  Target Milestone: ---

I believe this code should compile (and with MSVC it does), but with GCC it
does not:

    template<typename Arg>
    auto & C(Arg && arg) { return arg; }

    void DecltypeWithinLambda()
    {
        int i = 0;
        [[maybe_unused]] auto l = [i]() // mutable
        {
            // does not preserve constness of 'i' within non-mutable lambda
            // Seems to be evaluating it as if referencing the outer 'i'
            // Though, decltype((i)) does do the right thing.
            // alternative solution to mutable is to 'rename' the captured
variable list in the capture spec
            using T = decltype(C(i));
            [[maybe_unused]] T t(C(i)); // actual use of C() only matches
decltype if mutable
        };
    }

GCC says the last line is invalid:

    error: binding reference of type 'T' {aka 'int&'} to 'const int' discards
qualifiers
    | [[maybe_unused]] T t(C(i)); // actual use of C() only matches decltype if
mutable
    |                      ~^~~

If the lambda is marked mutable, it compiles as expected.  So does this, which
seems like it should be equivalent to the above:

    struct F
    {
        void DecltypeWithinConstMethod() const
        {
            using T = decltype(C(i));
            [[maybe_unused]] T t(C(i)); // actual use of C() matches decltype
        }
        int i;
    };

Demo: https://gcc.godbolt.org/z/PzEodY1bW

A somewhat similar bug, but not the same:
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=63192

^ permalink raw reply	[flat|nested] 2+ messages in thread

* [Bug c++/110752] decltype in lambda loses const qualifier unless lambda is mutable
  2023-07-20 13:57 [Bug c++/110752] New: decltype in lambda loses const qualifier unless lambda is mutable jzwinck at gmail dot com
@ 2023-11-10 16:12 ` ppalka at gcc dot gnu.org
  0 siblings, 0 replies; 2+ messages in thread
From: ppalka at gcc dot gnu.org @ 2023-11-10 16:12 UTC (permalink / raw)
  To: gcc-bugs

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=110752

Patrick Palka <ppalka at gcc dot gnu.org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
         Resolution|---                         |DUPLICATE
             Status|UNCONFIRMED                 |RESOLVED
                 CC|                            |ppalka at gcc dot gnu.org

--- Comment #1 from Patrick Palka <ppalka at gcc dot gnu.org> ---
dup of PR86697 it seems

*** This bug has been marked as a duplicate of bug 86697 ***

^ permalink raw reply	[flat|nested] 2+ messages in thread

end of thread, other threads:[~2023-11-10 16:12 UTC | newest]

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2023-07-20 13:57 [Bug c++/110752] New: decltype in lambda loses const qualifier unless lambda is mutable jzwinck at gmail dot com
2023-11-10 16:12 ` [Bug c++/110752] " ppalka at gcc dot gnu.org

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