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* [gcc r10-10170] Fortran: resolve expressions during SIZE simplification
@ 2021-10-05 19:51 Harald Anlauf
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From: Harald Anlauf @ 2021-10-05 19:51 UTC (permalink / raw)
To: gcc-cvs
https://gcc.gnu.org/g:dea2e6c7b5af2ec620fd94d824f006440907a34d
commit r10-10170-gdea2e6c7b5af2ec620fd94d824f006440907a34d
Author: Harald Anlauf <anlauf@gmx.de>
Date: Thu Sep 30 20:29:31 2021 +0200
Fortran: resolve expressions during SIZE simplification
gcc/fortran/ChangeLog:
PR fortran/102458
* simplify.c (simplify_size): Resolve expressions used in array
specifications so that SIZE can be simplified.
gcc/testsuite/ChangeLog:
PR fortran/102458
* gfortran.dg/pr102458b.f90: New test.
(cherry picked from commit b19bbfb1482505367dd19ae4ab1ea19e36802b6a)
Diff:
---
gcc/fortran/simplify.c | 5 +++++
gcc/testsuite/gfortran.dg/pr102458b.f90 | 21 +++++++++++++++++++++
2 files changed, 26 insertions(+)
diff --git a/gcc/fortran/simplify.c b/gcc/fortran/simplify.c
index d28aa7a3c16..48a109c1481 100644
--- a/gcc/fortran/simplify.c
+++ b/gcc/fortran/simplify.c
@@ -7379,6 +7379,7 @@ simplify_size (gfc_expr *array, gfc_expr *dim, int k)
mpz_t size;
gfc_expr *return_value;
int d;
+ gfc_ref *ref;
/* For unary operations, the size of the result is given by the size
of the operand. For binary ones, it's the size of the first operand
@@ -7435,6 +7436,10 @@ simplify_size (gfc_expr *array, gfc_expr *dim, int k)
return simplified;
}
+ for (ref = array->ref; ref; ref = ref->next)
+ if (ref->type == REF_ARRAY && ref->u.ar.as)
+ gfc_resolve_array_spec (ref->u.ar.as, 0);
+
if (dim == NULL)
{
if (!gfc_array_size (array, &size))
diff --git a/gcc/testsuite/gfortran.dg/pr102458b.f90 b/gcc/testsuite/gfortran.dg/pr102458b.f90
new file mode 100644
index 00000000000..3e1026e635a
--- /dev/null
+++ b/gcc/testsuite/gfortran.dg/pr102458b.f90
@@ -0,0 +1,21 @@
+! { dg-do compile }
+! { dg-options "-fdump-tree-original" }
+! { dg-final { scan-tree-dump-times "_gfortran_stop_numeric" 0 "original" } }
+! PR fortran/102458
+
+subroutine s4
+ integer, parameter :: n = 4
+ integer :: w(transfer(n, n)) = 1
+ integer :: x(transfer(n, n))
+ integer :: y(2*int(n) - n)
+ type t
+ integer :: z(int(n))
+ end type t
+ type(t) :: tt, uu(3)
+ integer, parameter :: i = size (w)
+ integer, parameter :: k = size (x)
+ integer, parameter :: m = size (y)
+ integer, parameter :: j = size (tt% z)
+ integer, parameter :: l = size (uu(2)% z)
+ if (i /= n .or. k /= n .or. m /= n .or. j /= n .or. l /= n) stop 1
+end
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