Re: declaring a protected member function as friend

Re: declaring a protected member function as friend

[Philippe Haution]

Hello,

This might answer to your question :
"A name nominated by a friend declaration shall be
accessible in the scope of the class containing the
friend declaration." (ISO C++ standard 11.4.7)

Regards,

PH
--- Ralph Gauges <ralph@isis.local> wrote:
> Hi,
> 
> I recently installed gcc4 (20050130) on some of my
> machines and all of the sudden I can not compile
> some code that worked fine with gcc 3.3 (20030304).
> Suddenly if a declare a friend function in some
> class that is a protected member function in another
> class gcc4 complains that the function is protected
> in this context. This is actually correct, but I
> could not find any documentation that this was not
> allowed in C++. Am I doing something wrong, or is
> this a bug since it worked with gcc3?
> 
> Ralph
> 
> Here is some sample code that compiles on gcc 3.3
> and fails on gcc 4.0
> 
> class A{
> Â Â Â  protected:
> Â Â Â Â Â Â Â  void test(){};
> };
> 
> class B{
> Â Â Â  public:
> Â Â Â Â Â Â Â  friend void A::test();
> };
> 


	

	
		
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Re: declaring a protected member function as friend

[Stuart Brooks]

> This might answer to your question :
> "A name nominated by a friend declaration shall be
> accessible in the scope of the class containing the
> friend declaration." (ISO C++ standard 11.4.7)

To clarify, does this then mean that one can never allow a protected method
from class A to have friend access to class B? While this may be in the
standard, it doesn't make sense to me as the friend declaration is not
*calling* the protected method, but allowing the protected method friend
access to itself, which is completely different.

Also, does this then carry over to friend classes? As in ...

class A
{
public:
  void pubFunc();
protected:
  void protFunc();
};

class B
{
protected:
  friend class A;
};

Does this then mean that A::protFunc() doesn't have protected access to B?

declaring a protected member function as friend

[Ralph Gauges]

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Hi,

I recently installed gcc4 (20050130) on some of my machines and all of the sudden I can not compile some code that worked fine with gcc 3.3 (20030304).
Suddenly if a declare a friend function in some class that is a protected member function in another class gcc4 complains that the function is protected in this context. This is actually correct, but I could not find any documentation that this was not allowed in C++. Am I doing something wrong, or is this a bug since it worked with gcc3?

Ralph

Here is some sample code that compiles on gcc 3.3 and fails on gcc 4.0

class A{
    protected:
        void test(){};
};

class B{
    public:
        friend void A::test();
};