* -Wlto-type-mismatch during lto with flexible array members in mixed C & C++ codebase
@ 2022-01-12 8:57 Hans-Joerg Schurr
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From: Hans-Joerg Schurr @ 2022-01-12 8:57 UTC (permalink / raw)
To: gcc-help
I'm in the process of adding some C++ code to a C codebase. This codebase uses
flexible array members in structs. In my understanding GCC supports this as a
compiler extension. If I compile my code with lto I get a -Wlto-type-mismatch
warning.
I added a minimal example to the end of this mail.
If I compile the example with
> gcc -c -flto a_struct.c
> g++ -c -flto b_struct.cc
> g++ -Wlto-type-mismatch a_struct.o b_struct.o
the last command prints
> a_struct.c:3:17: warning: type of ‘my_struct’ does not match original
declaration [-Wlto-type-mismatch]
> [...]
The example is taken from this bug report:
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=81440
where GCC erroneously produced this warning for pure C code.
Nevertheless, I suspect that in my case the reason for this warning is some
error on my side on mixing C and C++.
I would be happy if you have any insight into this.
(I'm using gcc version 10.3.0)
// ab_struct.h
typedef struct {
int i;
int ints[];
} struct_t;
// a_struct.c
#include "ab_struct.h"
extern struct_t my_struct;
int main() {
return my_struct.ints[0];
}
// b_struct.cc
#include "ab_struct.h"
struct_t my_struct = {
20,
{ 1, 2 }
};
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2022-01-12 8:57 -Wlto-type-mismatch during lto with flexible array members in mixed C & C++ codebase Hans-Joerg Schurr
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