Re: c++/2957: -pedantic: parse error

Re: c++/2957: -pedantic: parse error

[Artem Khodush]

The following reply was made to PR c++/2957; it has been noted by GNATS.

From: "Artem Khodush" <artem@duma.gov.ru>
To: <gcc-gnats@gcc.gnu.org>
Cc: <87000-quiet@bugs.debian.org>, <gcc-bugs@gcc.gnu.org>
Subject: Re: c++/2957: -pedantic: parse error
Date: Mon, 28 May 2001 14:30:49 +0400

 Matthias Klose wrote:
 > 
 > example below compiled witch -pedantic makes: 
 >  
 > $ g++-3.0 -pedantic foo.cc 
 > foo.cc: In function `int foo()': 
 > foo.cc:8: parse error before `;' token 
 >  
 > w/o -pedantic it is ok.  
 >  
 >  
 > #include <vector> 
 >  
 > using namespace std; 
 >  
 > template<class T> 
 > int foo() 
 > { 
 >         vector<T>::iterator i; /* this line: parse error before ';' */ 
 > } 
 
 standard-conforming code must use typename here:
 
 typename vector<T>::iterator i;
 
 but gcc detects this only in pedantic mode.
 
 (the compiler does not know that vector<T>::iterator is always a type 
 for an arbitrary value of T, hence the parse error).
 
 
 
 

Re: c++/2957: -pedantic: parse error

[Gabriel Dos Reis]

The following reply was made to PR c++/2957; it has been noted by GNATS.

From: Gabriel Dos Reis <gdr@codesourcery.com>
To: 87000-quiet@bugs.debian.org
Cc: gcc-gnats@gcc.gnu.org
Subject: Re: c++/2957: -pedantic: parse error
Date: 27 May 2001 11:14:04 +0200

 Matthias Klose <doko@cs.tu-berlin.de> writes:
 
 | #include <vector> 
 |  
 | using namespace std; 
 |  
 | template<class T> 
 | int foo() 
 | { 
 |         vector<T>::iterator i; /* this line: parse error before ';' */ 
 
 That is correct behaviour. vector<T>::iterator is a dependent name. So
 by default it is not parsed as a type-name.  To convince the compiler
 to take it as a type, then you need to say
 
     typename vector<T>::itertor i;
     ^^^^^^^^
 
 -- Gaby
 CodeSourcery, LLC                       http://www.codesourcery.com

c++/2957: -pedantic: parse error

[Matthias Klose]

>Number:         2957
>Category:       c++
>Synopsis:       -pedantic: parse error
>Confidential:   no
>Severity:       non-critical
>Priority:       low
>Responsible:    unassigned
>State:          open
>Class:          sw-bug
>Submitter-Id:   net
>Arrival-Date:   Sat May 26 11:16:01 PDT 2001
>Closed-Date:
>Last-Modified:
>Originator:     Debian BTS #87000
>Release:        3.0 20010526 (Debian prerelease) (Debian testing/unstable)
>Organization:
Debian
>Environment:
System: Linux smile 2.2.17 #1 Sun Oct 8 19:26:41 MEST 2000 i686 unknown
Architecture: i686

	
host: i386-pc-linux-gnu
build: i386-pc-linux-gnu
target: i386-pc-linux-gnu
configured with: ../src/configure -v --enable-languages=c,c++,java,f77,proto,objc --prefix=/usr --infodir=/share/info --mandir=/share/man --enable-shared --with-gnu-as --with-gnu-ld --with-system-zlib --enable-long-long --enable-nls --without-x --without-included-gettext --disable-checking --enable-threads=posix --enable-java-gc=boehm --with-cpp-install-dir=bin --enable-objc-gc i386-linux
>Description:
	
example below compiled witch -pedantic makes: 
 
$ g++-3.0 -pedantic foo.cc 
foo.cc: In function `int foo()': 
foo.cc:8: parse error before `;' token 
 
w/o -pedantic it is ok.  
 
 
#include <vector> 
 
using namespace std; 
 
template<class T> 
int foo() 
{ 
        vector<T>::iterator i; /* this line: parse error before ';' */ 
} 
 
 
int main(){return 0;} 
>How-To-Repeat:
>Fix:
>Release-Note:
>Audit-Trail:
>Unformatted: