Re: c/4142: gcc compiles C code with assignments to const variables

Re: c/4142: gcc compiles C code with assignments to const variables

[rodrigc]

Synopsis: gcc compiles C code with assignments to const variables

State-Changed-From-To: open->closed
State-Changed-By: rodrigc
State-Changed-When: Sun Feb 24 09:29:10 2002
State-Changed-Why:
    Using g++, this will not compile.
    If you use gcc, then use -pedantic-errors to treat the
    warnings as errors which will prevent the code from compiling.

http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&pr=4142

c/4142: gcc compiles C code with assignments to const variables

[RDahlsted]

>Number:         4142
>Category:       c
>Synopsis:       gcc compiles C code with assignments to const variables
>Confidential:   no
>Severity:       serious
>Priority:       medium
>Responsible:    unassigned
>State:          open
>Class:          sw-bug
>Submitter-Id:   net
>Arrival-Date:   Mon Aug 27 11:06:00 PDT 2001
>Closed-Date:
>Last-Modified:
>Originator:     Richard Dahlstedt
>Release:        gcc-2.7.2, gcc-2.95.2
>Organization:
>Environment:
Solaris 2.5 (gcc-2.7.2), Solaris 5.7 (gcc-2.95.2)
>Description:
    When compiling C code, this apparently is resolved when using g++ instead of gcc or when compiling C++ code through gcc (as it presumably will call g++), gcc will issue a warning about assignment to a const variable but will allow this to occur any way and create the executable.  Even when using the -ansi and -pedantic flags gcc will still create the executable with assignments being made to the const variable.  Unless I am missing something about the C standard and other C/C++ compiler vendors apparently agree with me, in that there products do not allow such to occur, I would like to know why gcc allows this C-specific issue to occur.
>How-To-Repeat:
#include <stdio.h>

void main(void)
{
  const int i = 0;

  i = 1;

  printf("i = %i\n", i);

  i = 2;

  printf("i = %i\n", i);
}
>Fix:

>Release-Note:
>Audit-Trail:
>Unformatted: