[Bug gdb/9837] New: sizeof( int(*)(int *) ) == 1?

[Bug gdb/9837] New: sizeof( int(*)(int *) ) == 1?

[chris dot interim at gmail dot com]

Walk up to a machine with gdb.
Run gdb.
Type "print sizeof( int(*)(int *) )"

The result comes back as "1".

I believe on most machines the answer should be 4.  Maybe 8 on some.
You might even have one that comes back with 2 if you're into antiques.

But 1?

All of the components of this (function pointer, int, int pointer) have a
size greater than 1.

-- 
           Summary: sizeof( int(*)(int *) ) == 1?
           Product: gdb
           Version: 6.8
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: gdb
        AssignedTo: unassigned at sourceware dot org
        ReportedBy: chris dot interim at gmail dot com
                CC: gdb-prs at sourceware dot org
 GCC build triplet: i386-redhat-linux
  GCC host triplet: i386-redhat-linux
GCC target triplet: i386-redhat-linux


http://sourceware.org/bugzilla/show_bug.cgi?id=9837

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[Bug gdb/9837] sizeof( int(*)(int *) ) == 1?

[drow at false dot org]

------- Additional Comments From drow at false dot org  2009-02-11 20:37 -------
Subject: Re:  New: sizeof( int(*)(int *) ) == 1?

On Wed, Feb 11, 2009 at 08:18:35PM -0000, chris dot interim at gmail dot com wrote:
> Walk up to a machine with gdb.
> Run gdb.
> Type "print sizeof( int(*)(int *) )"
> 
> The result comes back as "1".

Try this to see the underlying problem:

(gdb) ptype int(*)(int *)
type = int ()

I can't find it now, but there should be another bug open about the
problems with function pointer types.



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http://sourceware.org/bugzilla/show_bug.cgi?id=9837

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[Bug gdb/9837] sizeof( int(*)(int *) ) == 1?

[chris dot interim at gmail dot com]

------- Additional Comments From chris dot interim at gmail dot com  2009-02-11 22:17 -------
For completeness:

gdb
GNU gdb Fedora (6.8-23.fc9)
Copyright (C) 2008 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.  Type "show copying"
and "show warranty" for details.
This GDB was configured as "i386-redhat-linux-gnu".
(gdb) print sizeof( int(*)(int *) )
$1 = 1
(gdb) ptype int(*)(int *)
type = int ()
(gdb) print sizeof( int () )
$2 = 1
(gdb) print sizeof( int )
$3 = 4
(gdb) print sizeof( int * )
$4 = 4
(gdb) quit


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http://sourceware.org/bugzilla/show_bug.cgi?id=9837

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[Bug gdb/9837] sizeof( int(*)(int *) ) == 1?

[muhammad_bilal at mentor dot com]

http://sourceware.org/bugzilla/show_bug.cgi?id=9837

bilal <muhammad_bilal at mentor dot com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
         Resolution|                            |FIXED

--- Comment #4 from bilal <muhammad_bilal at mentor dot com> 2012-12-31 04:58:26 UTC ---
Hi All 
i think that, This is not a bug its only a gcc grammatical rule

Thanks
Bilal

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[Bug gdb/9837] sizeof( int(*)(int *) ) == 1?

[muhammad_bilal at mentor dot com]

http://sourceware.org/bugzilla/show_bug.cgi?id=9837

bilal <muhammad_bilal at mentor dot com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |muhammad_bilal at mentor
                   |                            |dot com

--- Comment #3 from bilal <muhammad_bilal at mentor dot com> 2012-12-31 04:53:50 UTC ---
Hi ALL
The sizeof operator return 1 when it operates on function name like 
e.g
sizeof(int())=1
sizeof(float())=1
sizeof(main)=1
sizeof(printf)=1
etc
Its the gcc grammatical rule

the problem discuss here

http://stackoverflow.com/questions/3838866/what-is-the-sizeofmain-sizeofprintf-sizeofscanf


Regards,
Bilal

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