From: Per Bothner <per@bothner.com>
To: Duncan Mak <duncanmak@gmail.com>,
kawa mailing list <kawa@sourceware.org>
Subject: Re: How to set procedure name in macros
Date: Mon, 02 Jan 2017 00:37:00 -0000 [thread overview]
Message-ID: <5f2e6df0-498b-735d-65a5-33a0d7c68d9d@bothner.com> (raw)
In-Reply-To: <CABgWrqrBnhkHXSjj8y6dAK1iVMS42Fnzc0tmWbBckuQkQtbXGA@mail.gmail.com>
On 01/01/2017 02:59 PM, Duncan Mak wrote:
> Hello all,
>
> Happy new year!
>
> In my DEFINE-FOO macro and I noticed that I can't control the name of
> the lambda in the syntax expansion.
This works:
(define-syntax define-d
(lambda (stx)
(syntax-case stx ()
((_ n) #`(define n (letrec ((foo (lambda () #f)))
(set-procedure-property! foo 'name 'n)
foo))))))
First, you needs to quite the property value.
Secondly, you should not use the same identifier for the syntax parameter
as the name" keyword.
I'm not clear why the following doesn't work - I'm looking into it.
(define-syntax define-c
(lambda (stx)
(syntax-case stx ()
((_ n) #`(define n (letrec ((foo (lambda () name: 'n
#f)))
foo))))))
--
--Per Bothner
per@bothner.com http://per.bothner.com/
next prev parent reply other threads:[~2017-01-02 0:37 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2017-01-01 23:00 Duncan Mak
2017-01-02 0:37 ` Per Bothner [this message]
2017-01-02 2:51 ` Duncan Mak
2017-01-02 2:54 ` Duncan Mak
2017-01-02 14:17 ` Per Bothner
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