Re: [PATCH v2] stdio-common/printf-prs.c: Reword comment

[Adhemerval Zanella <adhemerval.zanella@linaro.org>]

On 24/03/2021 15:29, Alejandro Colomar via Libc-alpha wrote:
> 'this' can be understood as the current parameter, but in this case it
> is meaning the other one, the one holding the width/precission.
> 
> 'it' better describes that parameter, differentiating it from the
> one corresponding to the current specifier.
> 
> Signed-off-by: Alejandro Colomar <alx.manpages@gmail.com>

We don't use SCO, but rather Copyright assignment.  The rest looks good
to me (although I am not a native speaker).

Reviewed-by: Adhemerval Zanella  <adhemerval.zanella@linaro.org>

> ---
>  stdio-common/printf-prs.c | 4 ++--
>  1 file changed, 2 insertions(+), 2 deletions(-)
> 
> diff --git a/stdio-common/printf-prs.c b/stdio-common/printf-prs.c
> index 1d4e00553d..8ebf09a0a9 100644
> --- a/stdio-common/printf-prs.c
> +++ b/stdio-common/printf-prs.c
> @@ -72,11 +72,11 @@ parse_printf_format (const char *fmt, size_t n, int *argtypes)
>        /* Parse this spec.  */
>        nargs += __parse_one_specmb (f, nargs, &spec, &max_ref_arg);
>  
> -      /* If the width is determined by an argument this is an int.  */
> +      /* If the width is determined by an argument, it is an int.  */
>        if (spec.width_arg != -1 && (size_t) spec.width_arg < n)
>  	argtypes[spec.width_arg] = PA_INT;
>  
> -      /* If the precision is determined by an argument this is an int.  */
> +      /* If the precision is determined by an argument, it is an int.  */
>        if (spec.prec_arg != -1 && (size_t) spec.prec_arg < n)
>  	argtypes[spec.prec_arg] = PA_INT;
>  
>