* issetugid - not declared when _XOPEN_SOURCE is also defined
@ 2016-11-09 18:13 cyg Simple
2016-11-09 19:41 ` cyg Simple
0 siblings, 1 reply; 4+ messages in thread
From: cyg Simple @ 2016-11-09 18:13 UTC (permalink / raw)
To: cygwin
The following program demonstrates the issue. Should issetugid be
declared with this scenario?
/*****************************************************/
#define _XOPEN_SOURCE 1 /* Causes declare warning */
#define __BSD_VISIBLE 1
#include <unistd.h>
int main(int argc, char ** argv) {
int result;
result = issetugid();
}
/****************************************************/
--
cyg Simple
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^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: issetugid - not declared when _XOPEN_SOURCE is also defined
2016-11-09 18:13 issetugid - not declared when _XOPEN_SOURCE is also defined cyg Simple
@ 2016-11-09 19:41 ` cyg Simple
2016-11-10 9:10 ` Corinna Vinschen
0 siblings, 1 reply; 4+ messages in thread
From: cyg Simple @ 2016-11-09 19:41 UTC (permalink / raw)
To: cygwin
On 11/9/2016 1:13 PM, cyg Simple wrote:
> The following program demonstrates the issue. Should issetugid be
> declared with this scenario?
>
> /*****************************************************/
> #define _XOPEN_SOURCE 1 /* Causes declare warning */
> #define __BSD_VISIBLE 1
> #include <unistd.h>
>
> int main(int argc, char ** argv) {
> int result;
> result = issetugid();
> }
> /****************************************************/
>
Because when _XOPEN_SOURCE is 1 _DEFAULT_SOURCE doesn't get set which
then #undef __BSD_VISIBLE and and sets it to 0. See
/usr/include/sys/features.h.
If I #define _DEFAULT_SOURCE 1 before the #include then the above code
works. However, should it?
--
cyg Simple
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* Re: issetugid - not declared when _XOPEN_SOURCE is also defined
2016-11-09 19:41 ` cyg Simple
@ 2016-11-10 9:10 ` Corinna Vinschen
2016-11-11 7:31 ` cyg Simple
0 siblings, 1 reply; 4+ messages in thread
From: Corinna Vinschen @ 2016-11-10 9:10 UTC (permalink / raw)
To: cygwin
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On Nov 9 14:41, cyg Simple wrote:
> On 11/9/2016 1:13 PM, cyg Simple wrote:
> > The following program demonstrates the issue. Should issetugid be
> > declared with this scenario?
> >
> > /*****************************************************/
> > #define _XOPEN_SOURCE 1 /* Causes declare warning */
> > #define __BSD_VISIBLE 1
> > #include <unistd.h>
> >
> > int main(int argc, char ** argv) {
> > int result;
> > result = issetugid();
> > }
> > /****************************************************/
> >
>
> Because when _XOPEN_SOURCE is 1 _DEFAULT_SOURCE doesn't get set which
> then #undef __BSD_VISIBLE and and sets it to 0. See
> /usr/include/sys/features.h.
>
> If I #define _DEFAULT_SOURCE 1 before the #include then the above code
> works. However, should it?
Yes. You have a bug in your code. Never (and I mean *never*) use the
__foo_VISIBLE macros in your code. Please read the long comment
preceeding the visibility macro handling in /usr/include/sys/features.h.
You want to use either _DEFAULT_SOURCE or _BSD_SOURCE (deprecated but
probably available for another 100 years).
Also, note the description of the __foo_VISIBLE macros later in the file.
It introduces the macros as "private" macros.
HTH,
Corinna
--
Corinna Vinschen Please, send mails regarding Cygwin to
Cygwin Maintainer cygwin AT cygwin DOT com
Red Hat
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^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: issetugid - not declared when _XOPEN_SOURCE is also defined
2016-11-10 9:10 ` Corinna Vinschen
@ 2016-11-11 7:31 ` cyg Simple
0 siblings, 0 replies; 4+ messages in thread
From: cyg Simple @ 2016-11-11 7:31 UTC (permalink / raw)
To: cygwin
On 11/10/2016 4:10 AM, Corinna Vinschen wrote:
> On Nov 9 14:41, cyg Simple wrote:
>> On 11/9/2016 1:13 PM, cyg Simple wrote:
>>> The following program demonstrates the issue. Should issetugid be
>>> declared with this scenario?
>>>
>>> /*****************************************************/
>>> #define _XOPEN_SOURCE 1 /* Causes declare warning */
>>> #define __BSD_VISIBLE 1
>>> #include <unistd.h>
>>>
>>> int main(int argc, char ** argv) {
>>> int result;
>>> result = issetugid();
>>> }
>>> /****************************************************/
>>>
>>
>> Because when _XOPEN_SOURCE is 1 _DEFAULT_SOURCE doesn't get set which
>> then #undef __BSD_VISIBLE and and sets it to 0. See
>> /usr/include/sys/features.h.
>>
>> If I #define _DEFAULT_SOURCE 1 before the #include then the above code
>> works. However, should it?
>
> Yes. You have a bug in your code. Never (and I mean *never*) use the
> __foo_VISIBLE macros in your code. Please read the long comment
> preceeding the visibility macro handling in /usr/include/sys/features.h.
> You want to use either _DEFAULT_SOURCE or _BSD_SOURCE (deprecated but
> probably available for another 100 years).
>
> Also, note the description of the __foo_VISIBLE macros later in the file.
> It introduces the macros as "private" macros.
Yea, I figured that out. I used __BSD_VISIBLE after looking at the
header for the function. Thanks for your time; sorry for wasting it.
--
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^ permalink raw reply [flat|nested] 4+ messages in thread
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2016-11-09 18:13 issetugid - not declared when _XOPEN_SOURCE is also defined cyg Simple
2016-11-09 19:41 ` cyg Simple
2016-11-10 9:10 ` Corinna Vinschen
2016-11-11 7:31 ` cyg Simple
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