[Bug gdb/12883] New: watchpoint on variable in function scope

[Bug gdb/12883] New: watchpoint on variable in function scope

[saugustine at google dot com]

http://sourceware.org/bugzilla/show_bug.cgi?id=12883

           Summary: watchpoint on variable in function scope
           Product: gdb
           Version: unknown
            Status: NEW
          Severity: normal
          Priority: P2
         Component: gdb
        AssignedTo: unassigned@sourceware.org
        ReportedBy: saugustine@google.com


Given the following program:

void foo() {
   static int i=0;
   ++i;
}
int main(int argc, char **argv) {
   foo();
   return 0;
}

Setting a watchpoint on foo::i works if the program is compiled as a C program,
but fails if the program is compiled as C++.

Not sure what the proper behavior is, but probably should be consistent from C
to C++.

$ gcc ~/bar.c -g
$ ./gdb ./a.out
GNU gdb (GDB) 7.2.90.20110513-cvs
...
(gdb) watch foo::i
Watchpoint 1: foo::i
(gdb) run
Starting program: ./a.out
Hardware watchpoint 1: foo::i

Old value = 0
New value = 1
foo () at /home/saugustine/bar.c:4
4       }

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[Bug gdb/12883] watchpoint on variable in function scope

[ssbssa at sourceware dot org]

https://sourceware.org/bugzilla/show_bug.cgi?id=12883

Hannes Domani <ssbssa at sourceware dot org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |ssbssa at sourceware dot org
             Status|NEW                         |RESOLVED
         Resolution|---                         |MOVED

--- Comment #1 from Hannes Domani <ssbssa at sourceware dot org> ---
Seems to have been a problem on gcc side, fixed some time ago, since it works
if you compile as c++ since at least gcc-5.2.

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